The circumcenter of a triangle is a special point where all three perpendicular bisectors of the triangle's sides meet. It's like finding the center of a circle that touches all three corners of the triangle!
To find the circumcenter, we use the coordinates of the triangle's three corners. It's like solving a puzzle to find the perfect spot that's equally far from all three points.
The magic formula for finding the circumcenter of a triangle with corners (x₁, y₁), (x₂, y₂), and (x₃, y₃) is:
\[ U_x = \frac{(x_1^2 + y_1^2)(y_2 - y_3) + (x_2^2 + y_2^2)(y_3 - y_1) + (x_3^2 + y_3^2)(y_1 - y_2)}{2[(x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2))]} \]
\[ U_y = \frac{(x_1^2 + y_1^2)(x_3 - x_2) + (x_2^2 + y_2^2)(x_1 - x_3) + (x_3^2 + y_3^2)(x_2 - x_1)}{2[(x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2))]} \]
Where:
Let's find the circumcenter of a triangle with corners at (0, 0), (4, 0), and (2, 3):
Step 1: We have (x₁, y₁) = (0, 0), (x₂, y₂) = (4, 0), (x₃, y₃) = (2, 3)
Step 2: \(D = 2[(0(0 - 3) + 4(3 - 0) + 2(0 - 0))] = 24\)
Step 3: \(U_x = \frac{(0^2 + 0^2)(0 - 3) + (4^2 + 0^2)(3 - 0) + (2^2 + 3^2)(0 - 0)}{24} = 2\)
Step 4: \(U_y = \frac{(0^2 + 0^2)(2 - 4) + (4^2 + 0^2)(0 - 2) + (2^2 + 3^2)(4 - 0)}{24} = 1.5\)
Step 5: The circumcenter is at (2, 1.5)
In this picture, you can see our blue triangle. The red dot is the circumcenter, where all three dashed lines (perpendicular bisectors) meet. The purple dashed circle is the circumcircle, which passes through all three corners of the triangle. Isn't it amazing how the circumcenter is exactly in the middle of this special circle?
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