Tube Calculator

radius r1 =
radius r2 =
circumference C1 =
circumference C2 =
wall thickness t =
height h =
volume V =
Let pi π =
h (Height) r₁ (Outer Radius) r₂ (Inner Radius) Key Formulas: Volume = πh(r₁² - r₂²) Surface Area = 2πh(r₁ + r₂) + 2π(r₁² - r₂²)

Tube Calculator

What is a Tube?

A tube, also known as a hollow cylinder or pipe, is a three-dimensional object with two concentric circular faces connected by two curved surfaces. It's characterized by its outer radius (r₁), inner radius (r₂), and height (h). Tubes are common in plumbing, construction, and industrial applications.

How to Calculate Tube Properties

To understand a tube fully, we need to calculate several key properties: its volume, surface area, and the relationship between inner and outer dimensions. Each of these properties is essential for engineering and design applications.

Formulas

Here are the essential formulas for a tube:

1. Volume (V):

\[ V = \pi h(r_1^2 - r_2^2) \]

2. Total Surface Area (A):

\[ A = 2\pi h(r_1 + r_2) + 2\pi(r_1^2 - r_2^2) \]

3. Wall Thickness (t):

\[ t = r_1 - r_2 \]

Where:

  • \(r_1\) is the outer radius
  • \(r_2\) is the inner radius
  • \(h\) is the height
  • \(t\) is the wall thickness
  • \(\pi\) (pi) is approximately 3.14159

Calculation Steps

  1. Determine the outer radius (r₁), inner radius (r₂), and height (h)
  2. Calculate the volume using \(V = \pi h(r_1^2 - r_2^2)\)
  3. Calculate the surface area using \(A = 2\pi h(r_1 + r_2) + 2\pi(r_1^2 - r_2^2)\)
  4. Calculate the wall thickness using \(t = r_1 - r_2\)

Example and Visual Representation

Let's calculate the properties of a tube with:

  • Outer radius (r₁) = 5 units
  • Inner radius (r₂) = 3 units
  • Height (h) = 10 units
  1. Volume: \(V = \pi(10)(5^2 - 3^2) = 502.65\) cubic units
  2. Surface Area: \(A = 2\pi(10)(5 + 3) + 2\pi(25 - 9) = 553.93\) square units
  3. Wall Thickness: \(t = 5 - 3 = 2\) units

Visual representation of the example tube:

h = 10 r₁ = 5 r₂ = 3 t = 2 Calculations: V = π×10×(5² - 3²) V = 502.65 cu units A = 2π×10×(5 + 3) + 2π×(25 - 9) A = 553.93 sq units

The diagram above shows a cross-sectional view of a tube, illustrating the outer radius (r₁), inner radius (r₂), and height (h). The shaded regions represent the solid material of the tube, while the hollow center shows the void space.